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GENERAL CHEESE MAKING BOARDS (Specific Cheese Making in Boards above) => STANDARD METHODS - Forming Cheese => Topic started by: countrygirl on November 02, 2010, 07:08:22 AM

Title: Pressing Cheeses - Pressure vs Size (The Snowshoe Effect)
Post by: countrygirl on November 02, 2010, 07:08:22 AM
Got a bit of a dilemma.
When a recipe says to press the cheese at a certain pressure, say 10 lbs, we find a big rock outside and weigh it and then press the cheese with this ie the cheese in the mold with a follower, a tin on top of it and the rock sitting on a plank that is counterbalanced with another rock and some big books. When the pressure requirement changes, we simply find a bigger rock.
Now I was wondering, when I use a larger mold we are actually not getting ten pounds of pressure (the snowshoe effect). Does anyone know the formula for calculating pressure or is it the  P = Force divided by area.

Might have to get some bigger rocks till the tradie in the house makes me a proper press!
Title: Re: Pressing Cheeses - Pressure vs Size (The Snowshoe Effect)
Post by: coffee joe on November 02, 2010, 10:02:59 AM
There are many previous threads on this subject. The "Snowshoe" effect you mentioned is related to PSI on the cheese. The bottom line is, depending upon the style of cheese you are making, as the mold gets wider you will need to find some very large rocks.
Title: Re: Pressing Cheeses - Pressure vs Size (The Snowshoe Effect)
Post by: Alex on November 02, 2010, 01:58:16 PM
QuoteP = Force divided by area.

That's perfectly correct !!!
Title: Re: Pressing Cheeses - Pressure vs Size (The Snowshoe Effect)
Post by: Sailor Con Queso on November 02, 2010, 02:05:52 PM
Country Girl, There are tons of discussions here. Just search the forum for PSI.